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Use back substitution to solve each of the following systems of equations: (a) x1-3 x2=2 2 x2=6 (b) x1+x2+x3=8 2 x2+x3 =5 3 x3 =9 (c) x1+2 x2+2 x3+x4=5 3 x2+x3-2 x4 =1 -x3+2 x4 =-1 4 x4 =4 (d) x1+x2+x3+x4+x5=5 2 x2+x3-2 x4+x5 =1 4 x3+x4-2 x5 =1 x4-3 x5 =0 2 x5 =2 | Numerade
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